Zadanie 15 strona 65 podręcznik matematyka z plusem 2
podpunkt B
15/65B.P<rombu>=e*f/2P=8*6/2P=48/2P=24p=π*r²p=π*2²p=4πP=24-4πC.P<trójkąta>=a*h/2P=5*6/2P=30/2=15p₁=π*r²p₁=π*1,5²p₁=2,25πp₂=π*0,5²p₂=0,25πP=15-(2,25π+0,25π)P=15-2,5π
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15/65
B.P<rombu>=e*f/2
P=8*6/2
P=48/2
P=24
p=π*r²
p=π*2²
p=4π
P=24-4π
C.P<trójkąta>=a*h/2
P=5*6/2
P=30/2=15
p₁=π*r²
p₁=π*1,5²
p₁=2,25π
p₂=π*0,5²
p₂=0,25π
P=15-(2,25π+0,25π)
P=15-2,5π