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ax+1=2x-a² dla x=2
2a+1=4-a²
a²+2a+1-4=0
Δ=4+4*3=16
a=1/2*(-2-4)=-3 v a=1/2*(-2+4)=1
4.
x²-1≠0
(x+1)(x-1)≠0
x+1≠0 i x-1≠0
D=R \ {-1, 1}
f(x)=[x²(x-1)]/[(x+1)(x-1)]=x²/(x+1)
f'(x)=(2x(x+1)-x²)/(x+1)²=(2x²+2x-x²)/(x+1)²=(x²+2x)/(x+1)²
D'=R \ {-1}