Zadania w załączniku. Dziękuje
m - 2n
√3 - 2 * (√3 -1) = √3 - 2√3 - 2 = -√3 - 2
n²
[2* ( √3 - 1)]² = [ 2√3 - 2 ] ² = 12 - 4 = 8
m*n
√3 * (2* (√3 - 1)] = √3 * ( 2√3 - 2 ) = 6 - 2 = 4
n/m
√3 / 2* ( √3 - 1) = √3 / 2√3 - 2 - obustronnie mnozymy * 2√3 -2
√3 * (2√3 - 2) / (2√3 - 2) * (2√3 - 2) = 4 / 1 = 4
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m - 2n
√3 - 2 * (√3 -1) = √3 - 2√3 - 2 = -√3 - 2
n²
[2* ( √3 - 1)]² = [ 2√3 - 2 ] ² = 12 - 4 = 8
m*n
√3 * (2* (√3 - 1)] = √3 * ( 2√3 - 2 ) = 6 - 2 = 4
n/m
√3 / 2* ( √3 - 1) = √3 / 2√3 - 2 - obustronnie mnozymy * 2√3 -2
√3 * (2√3 - 2) / (2√3 - 2) * (2√3 - 2) = 4 / 1 = 4