4)
mFe=56umFeO=56u+16u=72u2FeO + C ---> 2Fe + CO20,144kg FeO-------0,112kg Fe288kg FeO----------xkg Fex = 224kg Fe
6)
mH2O=18u
mH2=2u
2H2O ---> 2H2 + O2
36g H2O------4g H2
x = 4g H2
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4)
mFe=56u
mFeO=56u+16u=72u
2FeO + C ---> 2Fe + CO2
0,144kg FeO-------0,112kg Fe
288kg FeO----------xkg Fe
x = 224kg Fe
6)
mH2O=18u
mH2=2u
2H2O ---> 2H2 + O2
36g H2O------4g H2
x = 4g H2