Zad.2 Cialo spadlo z wysokosci 30m.Oblicz czas spadku i predkosci koncowa.Prosze o jak najprostsze rowiazanie :)
h = 30 m
g = 9,81 m/s² = 10 m/s²
V₀ = 0
t = ?
V = ?
h = g * t²/2
2h = g*t²
t² = 2h/g
t = √2h/g
t = √2*30 m/10 m/s²
t = √6 s²
t ≈ 2,45 s
h = a *t²/2 ; a = V/t
h = V/t*t²/2
h = V * t/2
2h = V * t
V = 2h/t
V = 2 *30 m/2,45 s
V = 60 m/2,45 s
V = 24,49 m/s
II sposób obl. V z zasady zachowania energii
Ep = Ek
m * g *h = m * V²/2
g * h = V²/2
2gh = V²
V = √2gh
V = √2 * 10 m/s²*30 m
V = √600 m²/s²
V ≈ 24,49 m/s
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h = 30 m
g = 9,81 m/s² = 10 m/s²
V₀ = 0
t = ?
V = ?
h = g * t²/2
2h = g*t²
t² = 2h/g
t = √2h/g
t = √2*30 m/10 m/s²
t = √6 s²
t ≈ 2,45 s
h = a *t²/2 ; a = V/t
h = V/t*t²/2
h = V * t/2
2h = V * t
V = 2h/t
V = 2 *30 m/2,45 s
V = 60 m/2,45 s
V = 24,49 m/s
II sposób obl. V z zasady zachowania energii
Ep = Ek
m * g *h = m * V²/2
g * h = V²/2
2gh = V²
V = √2gh
V = √2 * 10 m/s²*30 m
V = √600 m²/s²
V ≈ 24,49 m/s