zad.1.
Rozwiąż metodą podstawiana
a) 2x+y=3
x+y=2
b) x-y=3
4x+2y=6
c)3x-y+2=0
x+2y=-3
d) x+2y-3=-3
x+y+2=0
y= 3 - 2x
x + 3 - 2x = 2
x - 2x = 2 - 3
-x = -1 /: (-1)
x= 1
y= 3 - (2 *1)
y= 3 - 2
y= 1
x= 3 + y
4 (3+y) + 2y = 6
x= 3 +y
12 + 4y + 2y = 6
6y = 6 - 12
6y = -6 /:6
y= -1
x= 3 + (-1)
x= 2
3x - y = -2
x + 2y = -3
-y = -2 - 3x /: (-1)
y = 2 + 3x
x + 2 (2 + 3x) = -3
y= 2 + 3x
x + 4 + 6x = -3
7x = -3 - 4
7x = -7 /: 7
x = -1
y= 2 + 3 (-1)
x + 2y = 0
x + y = -2
x = 0 - 2y
0-2y + y = -2
x= 0 - 2y
-y = -2 /: (-1)
y= 2
x= 0 - 2* 2
x= -4
y = 2
a)
y=3-2x
x+3-2x=2
x=1
y=3-2
y=1
(1,1)
b)
x= 3+y
12+6y=6
x= 3-1
x=2
y=-1
(2,-1)- NIE ZAPOMNIJ O TYM !
c)
x=-3 - 2y
(-3-2y)*3-y+2=0
-9-6y-y+2=0
x=-3-2
x=-5
(-5,1)
d)
x=2y
3y+2=0
y= -2/3
x=-1 i 1/3
(-1 i 1/3, -2/3)
Myślę, że dobrze. Proszę naj :)
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a) 2x+y=3
x+y=2
y= 3 - 2x
x + 3 - 2x = 2
y= 3 - 2x
x - 2x = 2 - 3
y= 3 - 2x
-x = -1 /: (-1)
y= 3 - 2x
x= 1
y= 3 - (2 *1)
x= 1
y= 3 - 2
x= 1
y= 1
x= 1
b) x-y=3
4x+2y=6
x= 3 + y
4 (3+y) + 2y = 6
x= 3 +y
12 + 4y + 2y = 6
x= 3 + y
6y = 6 - 12
x= 3 + y
6y = -6 /:6
x= 3 + y
y= -1
x= 3 + (-1)
y= -1
x= 2
y= -1
c)3x-y+2=0
x+2y=-3
3x - y = -2
x + 2y = -3
-y = -2 - 3x /: (-1)
x + 2y = -3
y = 2 + 3x
x + 2 (2 + 3x) = -3
y= 2 + 3x
x + 4 + 6x = -3
y= 2 + 3x
7x = -3 - 4
y= 2 + 3x
7x = -7 /: 7
y= 2 + 3x
x = -1
y= 2 + 3 (-1)
x = -1
y= -1
x = -1
d) x+2y-3=-3
x+y+2=0
x + 2y = 0
x + y = -2
x = 0 - 2y
0-2y + y = -2
x= 0 - 2y
-y = -2 /: (-1)
x= 0 - 2y
y= 2
x= 0 - 2* 2
y= 2
x= -4
y = 2
a)
y=3-2x
x+3-2x=2
x=1
y=3-2
x=1
y=1
(1,1)
b)
x= 3+y
12+6y=6
y= -1
x= 3-1
x=2
y=-1
(2,-1)- NIE ZAPOMNIJ O TYM !
c)
x=-3 - 2y
(-3-2y)*3-y+2=0
-9-6y-y+2=0
y=1
x=-3-2
x=-5
x=-5
y=1
(-5,1)
d)
x=2y
3y+2=0
y= -2/3
x=-1 i 1/3
x=-1 i 1/3
y= -2/3
(-1 i 1/3, -2/3)
Myślę, że dobrze. Proszę naj :)