Zad.1Graniastosłup prosty ma w podstawie trójkąt prostokątny o bokach 1 dm,0,8dm,6 cm.Wysokość stano.... Question from @mirka63671

September 2018 3 13 Report

Zad.1Graniastosłup prosty ma w podstawie trójkąt prostokątny o bokach 1 dm,0,8dm,6 cm.Wysokość stanowi połowę sumy najkrótszej i najdłuższej krawędzi podstawy.Jaka jest objętość tej bryły?

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lobos896 A- 1dm=10cm
b-0,8dm=8cm
c- 6cm
H=(a+c)/2=(10+6)/2=16/2=8cm
p podst=8*6/2=24cm2
V=24*8=192cm3

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chrapek12 1 dm = 10 cm
0,8 dm = 8cm
1 cm

(10cm + 8cm) : 2 = 9 cm

8cm * 10cm : 2 = 40m2

40cm2 * 9cm = 360 cm3

Fly195 Ppodstawy= 6*8*1/2=24cm^2
wys= 6+10*1/2=16*1/2=8cm
v=24cm^2*8cm=192cm^3
Odp. Objętość tej bryły wynosi 192 cm^3.

w załączniku

Czy w dzisiejszych czasach istnienie takiej organizacji jak ONZ jest potrzebna? Swoją wypowiedź uzasadnij.prosze o pomoc potrzebuje na jutro

Jakie napięcie panuje na końcach przewodnika w którym przepływający ładunek 1 kulomba wykonał pracę 230 J.

w załaczniku

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