Zad1
a)2√3-3√3+5√3-7√3=
b)4∛2+∛2-3∛2-∛2=
c)3∛5-2∛2-∛5+4∛2=
d)2∛-2+4-4√5-3∛-2+6√5=
Zad2
Kwadraty mają pola 32cm²i 8cm². Oblicz sumę ich obwodów.
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zad. 1)
a)2√3-3√3+5√3-7√3=-3√3
b)4∛2+∛2-3∛2-∛2=∛2
c)3∛5-2∛2-∛5+4∛2=2∛5 + 2∛2 = 2(∛5 + ∛2)
d)2∛-2+4-4√5-3∛-2+6√5=-∛-2 + 4 + 2√5 = -∛-2 + 2(2 + √5)
zad. 2)
P = a*a (lub: a^2)
P(1) = 32cm²
32cm² = a*a
a(1) =
a(1) = cm
P(2) = 8cm²
8cm² = a*a
a(2) =
a(2) = cm
Obw(1) = 4a
Obw(1) = 4 *
Obw(1) = cm
Obw(2) = 4a
Obw(2) = 4 *
Obw(2) = cm
Obw = Obw(1) + Obw(2)
Obw = +
Obw = cm