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b) ⅓t²(.1..+½t³)=t²+1/2 t^5
c) 5a(5a²-0,2)=25a³-a
d) (12x²y+3xy²):6=2x²y+1/2xy²
e) (4y-6x): (-2)...=-2y+3x
f) (½t⁴-⅗w⁴): ...=...-⅕w⁴
⅓t²(3+½t³)=t²+1/6t⁵
5a(5a²-0,2)=25a³-a
(12x²y+3xy²):6=2x²y+½xy²
(4y-6x): (-2)=-2y+3x
(½t⁴-⅗w⁴): ...=...-⅕w⁴ -niestety nie wiem ;(