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|AB|²=(3+5)²+(-2-2)²=64+16=80
a=|AB|=4√5
Ob=3a
Ob=3*4√5=12√5
2.
a+a+r+a+2r=6 ⇒ 3a+3r=6 ⇒ a+r=2⇒ r=2-a
a(a+r)(a+2r)=-24
2a(a+2r)=-24 /:2
a(a+2(2-a))=-12
a(4-a)+12=0
-a²+4a+12=0
Δ=4²+4*12=16+48=64
a₁=-1/2*(-4-8)=6, r=2-6=-4 lub a₁=-1/2*(-4+8)=-2, r=4
Odp. Sa to liczby: 6, 2, -2 lub -2, 2, 6.