" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
(2x³+6x²-9x-4): ( x+4)=2x²-2x-1
-2x³-8x²
.............
= -2x²-9x-4
+2x²+8x
.....................
-x-4
+x+4
....................
Δ=4+8=12 √Δ=2√3
x1=-4 x2=[2-2√3]/4=(1-√3)/2 x3=(1+√3)/2
2x³+6x²-9x-4=2(x+4)[x- (1-√3)/2] [ x+(1+√3)/2 ]
b]
(x³-x²-8x+12):(x-2)=x²+x-6
-x³+2x²
...........
x²-8x+12
-x²+2x
..............
-6x+12
+6x-12
...............
Δ=1+24=25
x1=2 x2=[-1-5]/2=-3 x3=[-1+5]/2=2
x³-x²-8x+12=(x-2)²((x+3)
c]
(6x³-19x²+x+6): (x-3)=6x²-x-2
-6x³+18x²
................
-x²+x+6
+x²-3x
...................
-2x+6
+2x-6
.............
Δ=1+48=49
x1=3 x2=[1-7]/12=-1/2 x3=[1+7]/12=2/3
6x³-19x²+x+6=6(x-3)(x+1/2)(x-2/3)