Odpowiedź:
[tex]log_{4}3 = a\\\\a) log_{4}9 = log_{4}3^{2} = 2log_{4} 3\\log_{4}9 = 2a \\\\b) log_{4}12 = log_{4}(4*3) = log_{4}3 + log_{4}4 = a + 1\\\\c) log_{16}27 = log_{16}3^{3} =log_{4^{2}}3^{3} = \frac{3}{2} * log_{4}3 = \frac{3}{2}a[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Odpowiedź:
[tex]log_{4}3 = a\\\\a) log_{4}9 = log_{4}3^{2} = 2log_{4} 3\\log_{4}9 = 2a \\\\b) log_{4}12 = log_{4}(4*3) = log_{4}3 + log_{4}4 = a + 1\\\\c) log_{16}27 = log_{16}3^{3} =log_{4^{2}}3^{3} = \frac{3}{2} * log_{4}3 = \frac{3}{2}a[/tex]