Zad. Rozwiąż równania i nierówności.
a)
x²+8x-16=0
Δ=8²-4*1*(-16)Δ=64+64
Δ=128
√Δ=8√2
x₁=(-8-8√2)/(2*1)
x₁=-4-4√2
x₂=(-8+8√2)/(2*1)
x₂=-4+4√2
b)
6x²=-5x
6x²+5x=0
x(6x+5)=0
x=0
6x+5=0
6x=-5
x=-5/6
c)
5x-3=2x²
2x²-5x+3=0
2x²-2x-3x+3=0
2x(x-1)-3(x-1)=0
(2x-3)(x-1)=0
2x-3=0
2x=3
x=3/2 ∨ x=1
a) x²+8x-16=0
a=1
b=8
c=-16
Δ=b²-4ac
Δ=8²-4*1*(-16)=64+64=128
x₁=-b-√Δ:2a=-8-8√2:2*1=-8-8√2:2=-4-4√2
x₂=-b+√Δ:2a=-8+8√2:2*1=-8+8√2:2=-4+4√2
b)6x²=-5x
x=0 lub
6x=-5 /:6
c)5x-3=2x²
-2x²+5x-3=0
a=-2
b=5
c=-3
Δ=5²-4*(-2)*(-3)=25-24=1
Δ=1
√Δ=1
x₁=-b-√Δ:2a=-5-1:2*(-2)=-6:(-4)=1,5
x₂=-b+√Δ:2a=-5+1:2*(-2)=-4:(-4)=1
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a)
x²+8x-16=0
Δ=8²-4*1*(-16)
Δ=64+64
Δ=128
√Δ=8√2
x₁=(-8-8√2)/(2*1)
x₁=-4-4√2
x₂=(-8+8√2)/(2*1)
x₂=-4+4√2
b)
6x²=-5x
6x²+5x=0
x(6x+5)=0
x=0
6x+5=0
6x=-5
x=-5/6
c)
5x-3=2x²
2x²-5x+3=0
2x²-2x-3x+3=0
2x(x-1)-3(x-1)=0
(2x-3)(x-1)=0
2x-3=0
2x=3
x=3/2 ∨ x=1
a) x²+8x-16=0
a=1
b=8
c=-16
Δ=b²-4ac
Δ=8²-4*1*(-16)=64+64=128
Δ=128
√Δ=8√2
x₁=-b-√Δ:2a=-8-8√2:2*1=-8-8√2:2=-4-4√2
x₂=-b+√Δ:2a=-8+8√2:2*1=-8+8√2:2=-4+4√2
b)6x²=-5x
6x²+5x=0
x(6x+5)=0
x=0 lub
6x+5=0
6x=-5 /:6
x=-5/6
c)5x-3=2x²
-2x²+5x-3=0
a=-2
b=5
c=-3
Δ=b²-4ac
Δ=5²-4*(-2)*(-3)=25-24=1
Δ=1
√Δ=1
x₁=-b-√Δ:2a=-5-1:2*(-2)=-6:(-4)=1,5
x₂=-b+√Δ:2a=-5+1:2*(-2)=-4:(-4)=1