Question

zad 6 przyklad b.c
prosze na jutro ​

Answer 1

Odpowiedź:

b)

(8x⁻³y)³ : (4x⁻⁴y²)³ = 512x⁻⁹y³ : 64x⁻¹²y⁶ = 8x⁻⁹⁺¹²y³⁻⁶ = 8x³y⁻³ =

= 8 * (∛12)³ * (4√3)⁻³ = 8 * 12 * (1/4√3)³ = 96 * 1/(64 * 3√3) =

= 96/64 : 3√3 = 6/4 : 3√3 = 6/12√3 = 1/2√3 = √3/(2 * 3) = √3/6

c)

(x²y³)² * ( - 3x³y²)³/(- xy²)⁵ = (x⁴y⁶) * (- 27x⁹y⁶)/(- x⁵y¹⁰) =

= - 27x⁴⁺⁹y⁶⁺⁶/( - x⁵y¹⁰) = - 27x¹³y¹²/(- x⁵y¹⁰) = 27x¹³⁻⁵y¹²⁻¹⁰ = 27x⁸y²

27x⁸y² = 27 * (√3)⁸ * (1/9)² = 27 * (√3)² * (√3)² * (√3)² * (√3)² * 1/81 =

= 27 * 3 * 3 * 3 * 3 * 1/81  = 27 * 81 * 1/81 = 27 * 1 = 27

Szczegółowe wyjaśnienie: