zad. 3, 4, 5
Zad. 3)
a)
x = (27⁹ + 81⁷) : 9¹³
x = [(3³)⁹ + (3⁴)⁷] : (3²)¹³
x = (3²⁷ + 3²⁸) : 3²⁶
x = 3²⁶(3 + 3²) : 3²⁶
x = 3 + 9
x = 12
y = (8¹⁶ + 4²⁵) :(5 x 16¹²)
y = [(2³)¹⁶ + (2²)²⁵] : [5 x (2⁴)¹²]
y = (2⁴⁸ + 2⁵⁰) : (5 x 2⁴⁸)
y = ( 2⁴⁸ + 2⁴⁸ x 2²) : (5 x 2⁴⁸)
y = 2⁴⁸ x ( 1 + 2²) : (5 x 2⁴⁸)
y = 2⁴⁸ x ( 1 + 4) : (5 x 2⁴⁸)
y = (2⁴⁸ x 5) : (5 x 2⁴⁸)
y = 1
(x/y) * 100%
(12/1) * 100%
1200%
b)
x = (5⁻²⁰ + 5⁻¹⁹) : 125⁻⁶
x = (5⁻¹⁹ x 5⁻¹ + 5⁻¹⁹) : (5³)⁻⁶
x = 5⁻¹⁹ x (5⁻¹ + 1) : 5⁻¹⁸
x = 5⁻¹ x 1,2
x = 0,2 x 1,2
x = 0,24
y = [6⁻¹⁴ + 12 x (1/6)¹⁵] : [0,5¹⁴ x (1/3)¹⁵]
y = (6⁻¹⁴ + 12 x 6⁻¹⁵) : (0,5¹⁴ x 3⁻¹⁵)
y = 6⁻¹⁴ x (12 x 1/6) : (0,5¹⁴ x 3⁻¹⁵)
y = (6⁻¹⁴ x 2) : (0,5¹⁴ x 3⁻¹⁵)
y = (6⁻¹⁴ x 2) : (2⁻¹⁴ x 3⁻¹⁴ x 3⁻¹)
y = (6⁻¹⁴ x 2) : (6⁻¹⁴ x 3⁻¹)
y = 2 : (1/3)
y = 6
(0,24/6) * 100% = 0,04 * 100% = 4%
Zad. 4)
(2/3 - 2⁻²)⁻¹ = (2/3 - 1/4)⁻¹ =
= (8/12 - 3/12)⁻¹ =
= (5/12)⁻¹ =
= 12/5 =
= 2,4
[∛8⁻¹ - "pierw4st"(9⁻²)]⁻¹ = (0,5 - 1/3)⁻¹ =
= (3/6 - 2/6)⁻¹ =
= (4/6)⁻¹ =
= (2/3)⁻¹ =
= 3/2 =
= 1,5
c)
[(3/4)⁻¹ - (1,5)⁻¹]⁻² = (4/3 - 2/3)⁻² =
= (2/3)⁻² =
= 9/4 =
= 2,25
d)
[(1,25)⁻¹ - ∛8/27]⁻² = (0,8 - 2/3)⁻² =
= (4/5 - 2/3)⁻² =
= (12/15 - 10/15)⁻² =
= (2/15)⁻² =
= 225/4 =
= 56,25
Zad. 5)
√9 x [(1,5)⁻¹ + 9^(- 1,5)] x 27^(2/3) = 3 x (2/3 + 1/27) x 1/9 =
= 1/3 x (18/27 + 1/27) =
= 1/3 x 19/27 =
= 19/81
[(81/625)^( - 0,75) : (5/3)³ - (0,125)^(1/3)]⁻² = [(5/3)³ : (5/3)³ - 0,5]⁻² =
= (1 - 0,5)⁻² =
= 0,5⁻² =
= 4
∛0,375 x ∛9 + (3⁻¹ - "pierw4st"16/81)⁻² = (∛3,375 + 2/3)⁻² =
= (∛27/8 + 2/3)⁻² =
= (3/2 + 2/3)⁻² =
= (9/6 + 4/6)⁻² =
= (10/6)⁻² =
= (5/3)⁻² =
= 9/25 =
= 0,36
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Zad. 3)
a)
x = (27⁹ + 81⁷) : 9¹³
x = [(3³)⁹ + (3⁴)⁷] : (3²)¹³
x = (3²⁷ + 3²⁸) : 3²⁶
x = 3²⁶(3 + 3²) : 3²⁶
x = 3 + 9
x = 12
y = (8¹⁶ + 4²⁵) :(5 x 16¹²)
y = [(2³)¹⁶ + (2²)²⁵] : [5 x (2⁴)¹²]
y = (2⁴⁸ + 2⁵⁰) : (5 x 2⁴⁸)
y = ( 2⁴⁸ + 2⁴⁸ x 2²) : (5 x 2⁴⁸)
y = 2⁴⁸ x ( 1 + 2²) : (5 x 2⁴⁸)
y = 2⁴⁸ x ( 1 + 4) : (5 x 2⁴⁸)
y = (2⁴⁸ x 5) : (5 x 2⁴⁸)
y = 1
(x/y) * 100%
(12/1) * 100%
1200%
b)
x = (5⁻²⁰ + 5⁻¹⁹) : 125⁻⁶
x = (5⁻¹⁹ x 5⁻¹ + 5⁻¹⁹) : (5³)⁻⁶
x = 5⁻¹⁹ x (5⁻¹ + 1) : 5⁻¹⁸
x = 5⁻¹ x 1,2
x = 0,2 x 1,2
x = 0,24
y = [6⁻¹⁴ + 12 x (1/6)¹⁵] : [0,5¹⁴ x (1/3)¹⁵]
y = (6⁻¹⁴ + 12 x 6⁻¹⁵) : (0,5¹⁴ x 3⁻¹⁵)
y = 6⁻¹⁴ x (12 x 1/6) : (0,5¹⁴ x 3⁻¹⁵)
y = (6⁻¹⁴ x 2) : (0,5¹⁴ x 3⁻¹⁵)
y = (6⁻¹⁴ x 2) : (2⁻¹⁴ x 3⁻¹⁴ x 3⁻¹)
y = (6⁻¹⁴ x 2) : (6⁻¹⁴ x 3⁻¹)
y = 2 : (1/3)
y = 6
(0,24/6) * 100% = 0,04 * 100% = 4%
Zad. 4)
a)
(2/3 - 2⁻²)⁻¹ = (2/3 - 1/4)⁻¹ =
= (8/12 - 3/12)⁻¹ =
= (5/12)⁻¹ =
= 12/5 =
= 2,4
b)
[∛8⁻¹ - "pierw4st"(9⁻²)]⁻¹ = (0,5 - 1/3)⁻¹ =
= (3/6 - 2/6)⁻¹ =
= (4/6)⁻¹ =
= (2/3)⁻¹ =
= 3/2 =
= 1,5
c)
[(3/4)⁻¹ - (1,5)⁻¹]⁻² = (4/3 - 2/3)⁻² =
= (2/3)⁻² =
= 9/4 =
= 2,25
d)
[(1,25)⁻¹ - ∛8/27]⁻² = (0,8 - 2/3)⁻² =
= (4/5 - 2/3)⁻² =
= (12/15 - 10/15)⁻² =
= (2/15)⁻² =
= 225/4 =
= 56,25
Zad. 5)
a)
√9 x [(1,5)⁻¹ + 9^(- 1,5)] x 27^(2/3) = 3 x (2/3 + 1/27) x 1/9 =
= 1/3 x (18/27 + 1/27) =
= 1/3 x 19/27 =
= 19/81
b)
[(81/625)^( - 0,75) : (5/3)³ - (0,125)^(1/3)]⁻² = [(5/3)³ : (5/3)³ - 0,5]⁻² =
= (1 - 0,5)⁻² =
= 0,5⁻² =
= 4
c)
∛0,375 x ∛9 + (3⁻¹ - "pierw4st"16/81)⁻² = (∛3,375 + 2/3)⁻² =
= (∛27/8 + 2/3)⁻² =
= (3/2 + 2/3)⁻² =
= (9/6 + 4/6)⁻² =
= (10/6)⁻² =
= (5/3)⁻² =
= 9/25 =
= 0,36