zad 1 ZAPISZ W POSTACI ILOCZYNU (((PILNIE PROSZE O POMOC)))))
x(a+3) -2y(a+3)=
4a kwadrat(7+x) -3b kwadrat(x+7)=
5a kwadrat-5ax-7a+7x=
30ax-34bx-15a+17b=
x(b-a)-y(b-a)-z(b-a)=
a kwadrat(x-1)-b(x-1)=
3(x+1) kwadrat-2(x-1) kwadrat=
(x-3) kwadrat-(x+4) kwadrat=
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no to musisz x(a+3)-2y(a+3) i to podzzielic potem przez 6a