Zad 1. Rozwiąż równania:
a) 3(x-4)-2(2x-5)= -4
b) -2(x+3)+4(2x+3)= -6
c) 3(x-4)-4(2x-7)=2(x+5)
Proszę o pomoc
3x-12-4x+10=-4
-x=-2
x=2
-2x-6+8x+12=-6
6x=-12
x=-2
3x-12-8x+28=2x+10
-7x=6
x=-6/7
3(x-4)-2(2x-5)= -4
3x-4x=12-10-4
-1x=-2/ (-1)
-2(x+3)+4(2x+3)= -6
-2x-6+8x+12= -6
-2x+8x=6-12-6
6x=-12 /6
3(x-4)-4(2x-7)=2(x+5)
3x-8x-2x=12-28+10
-7x=-6 / (-7)
x=6/7
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a) 3(x-4)-2(2x-5)= -4
3x-12-4x+10=-4
-x=-2
x=2
b) -2(x+3)+4(2x+3)= -6
-2x-6+8x+12=-6
6x=-12
x=-2
c) 3(x-4)-4(2x-7)=2(x+5)
3x-12-8x+28=2x+10
-7x=6
x=-6/7
3(x-4)-2(2x-5)= -4
3x-12-4x+10=-4
3x-4x=12-10-4
-1x=-2/ (-1)
x=2
-2(x+3)+4(2x+3)= -6
-2x-6+8x+12= -6
-2x+8x=6-12-6
6x=-12 /6
x=-2
3(x-4)-4(2x-7)=2(x+5)
3x-12-8x+28=2x+10
3x-8x-2x=12-28+10
-7x=-6 / (-7)
x=6/7