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p= e*f/2
e=8cm
f=6cm
p=8*6/2
p=24cm2
O=4*5
O=20cm
a=6
h=4,5
6*4,5=27cm2
zad2.
e*f/w
8*6/2=24
O.rombu= 4a
O= 4*5 =20
licze na naj
pozdrawiam
a = 6cm
h = 0,75% z a - 0,75a
Pole rombu = a * h
P = 6cm * 0,75 * 6cm = 27cm²
Odp. Pole równoległoboku wynosi 27cm²
Zad. 2
e = 6cm
f = 8cm
P = 1/2 * e * f
P = 1/2 * 6cm * 8cm = 1/2 * 48cm² = 24cm²
Ob.
(1/2 * 6)² + (1/2 * 8)² = x²
3² + 4² = x²
25 = x² / *√
x = 5cm
Ob. 4 * 5cm = 20cm
Odp. Pole rombu wynosi 24cm² a obwód 20cm.