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460----------------------x (g)
92---------------------227
X=1135 g
co stanowi 1135/227=5 moli
pozdro.
C6H2CH3(NO2)3 - Trotyl
mC6H5CH3=7*12u+8*1u=92u
C6H5CH3 + 3HNO3-------->C6H2CH3(NO2)3 + 3H2O
92g toluenu---------------------1mol trotylu (z reakcji)
460g toluenu-------------------x moli trotylu (z treści zad.)
x=460/92
x=5 moli trotylu