zad 1 do 200g 20% roztworu zasady dodano 300g 5% roztworu tej zasady. Oblicz stezenie procentowe mieszaniny !
zad 2 napisz rownanie reakcji
Li --->Li2O--->LiOH
^------------------^
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Zad 1
Cp1= 20%
Cp2= 5%
mr1= 200g
mr2= 300g
wzór
Cp1 * mr1 + Cp2 * mr2 = Cp3 * (mr1 + mr2)
20% * 200g + 5% * 300g = x% * (200g + 300g)
40g + 15g = 0,01x% * 500g
55 = 5x / :5
x=11%
Odp. Stężenie otrzymanego roztworu wynosi 11%.
Zad2
4Li + O2 -> 2Li2O
Li2O + H2O -> 2LiOH