Z^4=(1+2i)^8
Na zasadach liczb zespolonych...
Z⁴ = (1 + 2i)⁸
Z⁴ = [(1 + 2i)²]⁴
z = (1 + 2i)²
z = 1 + 4i +(2i)² ⇒ należy pamiętać, że i² = -1, zatem
z = 1 + 4i - 4
z = -3 + 4i
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Z⁴ = (1 + 2i)⁸
Z⁴ = [(1 + 2i)²]⁴
z = (1 + 2i)²
z = 1 + 4i +(2i)² ⇒ należy pamiętać, że i² = -1, zatem
z = 1 + 4i - 4
z = -3 + 4i