Z talii 52 kart wylosowano 3 karty, jakie jest prawdopodobieństwo wylosowania A - dwóch waletów i asa.
N = ( 52 nad 3) = 52 ! / [ 3 ! * 49 ! ] = [ 50*51*52]/6 = 22 100
A - zdzreznie losowe : " wylosowano 2 walety i asa "
n( A) = ( 4 nad 2) *( 4 nad 1) = 6*4 = 24
zatem
P( A) = n( A) / N = 24 / 22 100 = 6/ 5 525
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N = ( 52 nad 3) = 52 ! / [ 3 ! * 49 ! ] = [ 50*51*52]/6 = 22 100
A - zdzreznie losowe : " wylosowano 2 walety i asa "
n( A) = ( 4 nad 2) *( 4 nad 1) = 6*4 = 24
zatem
P( A) = n( A) / N = 24 / 22 100 = 6/ 5 525
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