z podanego równania wyznacz xa(b+x)= a²c
a(b+x)= a²c /:a
b + x = ac
x = ac - b
ab+ax=a²c
ax=a²c-ab
dla a różnego od zera
x==ac-b
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a(b+x)= a²c /:a
b + x = ac
x = ac - b
ab+ax=a²c
ax=a²c-ab
dla a różnego od zera
x==ac-b