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2πr=10π
r=5
Pw=(πr²α):360°
Pw=(π5²72°):360°=5π
L=2πr/:2π
L/2π = r
r= 10πdm/2π
r=5dm
pole wycinka
P=alfa/360 × πr²
P=72°/360° × π (5dm)²
p=⅕ × π25dm²
P=⅕ × 25/1dm²π
P=5πdm²