Question

Z koła o promieniu r wyznaczono wycinek o obwodzie 10r . uzasadnij ze pole tego wycinka jest równe polu kwadratu o boku 2r .

Answer 1

2 * pi * R = 10r~~~ R = 10r : 2 * pi~~~ R = 5r : pi~~~ P' = pi * R^2~~~ P' = pi * (5r : pi)^2~~~ P' = pi * 25r^2 : pi^2~~~ P' = 25r^2 : pi~~~ P kwadratu = (2r)^2 P kwadratu = 4r^2

Answer 2

2 * pi * R = 10r
R = 10r : 2 * pi
R = 5r : pi

P' = pi * R^2
P' = pi * (5r : pi)^2
P' = pi * 25r^2 : pi^2
P' = 25r^2 : pi

P kwadratu = (2r)^2
P kwadratu = 4r^2