Z drutu o dlugosci 84cm kwadratowe zbudowano szkielet szescianu . Oblicz pole i objetosc
L = 84 cm
Długość mierzy się w cm , a nie w cm^2 !
zatem
a = L : 12 = 84 cm : 12 = 7 cm
Pole
P = 6* a^2 = 6 * 9 7 cm)^2 = 6 * 49 cm^2 = 294 cm^2
===============================================
Objetość
V = a^3 = ( 7 cm )^3 = 49*7 cm^3 = 343 cm^3
==========================================
a = 84cm :12 = 7 cm
P=6a² = 6 * 7²= 294[cm²]
V=a³ = 7³=343[cm³]
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L = 84 cm
Długość mierzy się w cm , a nie w cm^2 !
zatem
a = L : 12 = 84 cm : 12 = 7 cm
Pole
P = 6* a^2 = 6 * 9 7 cm)^2 = 6 * 49 cm^2 = 294 cm^2
===============================================
Objetość
V = a^3 = ( 7 cm )^3 = 49*7 cm^3 = 343 cm^3
==========================================
a = 84cm :12 = 7 cm
P=6a² = 6 * 7²= 294[cm²]
V=a³ = 7³=343[cm³]