z 200 gramów 20% roztworu odparowano 100 gramów wody.Obliczyć stężęnie otrzymanego roztworu.
200g*20%-100g*0%=100g*x%
4000=100x
x=40[%]
Dane:Cp₁=20%m rozt.= 200gm wody= 100gCp= ms/mr * 100% ms= (Cp*mr):100%ms₁= (20%*200g):100%=40g ms₁=ms₂ms₂=40g200g-100g=100gCp₂= ms/mr * 100%Cp₂= 40g/100g *100%=40%
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200g*20%-100g*0%=100g*x%
4000=100x
x=40[%]
Dane:
Cp₁=20%
m rozt.= 200g
m wody= 100g
Cp= ms/mr * 100%
ms= (Cp*mr):100%
ms₁= (20%*200g):100%=40g
ms₁=ms₂
ms₂=40g
200g-100g=100g
Cp₂= ms/mr * 100%
Cp₂= 40g/100g *100%=40%