y=x2-3x-10
postać kanoniczna i iloczynowa
p=3/2=1,5
Δ=9-4*1*(-10)
Δ=49
q=-49/8=-6,125
y=(x-1,5)²-6,125
√Δ=7
x1=5
x2=-2
y=(x+5)(x-2)
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y=x2-3x-10
p=3/2=1,5
Δ=9-4*1*(-10)
Δ=49
q=-49/8=-6,125
y=(x-1,5)²-6,125
√Δ=7
x1=5
x2=-2
y=(x+5)(x-2)