Volume prisma segitiga
[tex] \frac{1}{2} \times alas \times t \:∆ \times t \: prisma \\ \frac{1}{2} \times 24 \: cm \times 9 \: cm \times 36 \: cm \\ 3.888 \: {cm}^{3} \\ \\ m = \sqrt{ {(a} \div 2)^{2} + {t}^{2} } \\ m= \sqrt{ {(24 \div 2)}^{2} + {9}^{2} } \\ m = \sqrt{144 + 81} = \sqrt{225} \\ m = 15 \\ \\ luas \: permukaan \: segitiga \\ (a \times t) + (a + m + m) \times tp) \\ (24 \times 9) + (24 + 15 + 15) \times 36) \\ 216 + (54 \times 36) \\ 216 + 1.944 \\ 2.160 \: {cm}^{2} [/tex]
Jawaban:
Diketahui
alas = 24 cm
tinggi alas = 9 cm
tinggi prisma = 36 cm
Ditanya
a) Volume = ?
b) Luas permukaan = ?
Jawab
V = Luas Alas x Tinggi Prisma
V = ( ½ x 24 x 9) x 36
V = 12 x 9 x 36
V = 3.888 cm³
Panjang IF
IF² = 12² + 9²
IF² = 144 + 81
IF = √225
IF = 15 cm
Luas permukaan prisma
= Luas selimut + 2 x luas alas
Luas selimut
= ( 24 x 36) + ( 15 x 36) + ( 15 x 36)
= 864 + 540 + 540
= 1944 cm²
Luas alas
= 2 x ( ½ x 24 x 9)
= 2 x ( 12 x 9)
= 2 x 108
= 216 cm²
Jadi luas permukaan prisma adalah 1944 + 216 = 2160 cm²
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Verified answer
Volume prisma segitiga
[tex] \frac{1}{2} \times alas \times t \:∆ \times t \: prisma \\ \frac{1}{2} \times 24 \: cm \times 9 \: cm \times 36 \: cm \\ 3.888 \: {cm}^{3} \\ \\ m = \sqrt{ {(a} \div 2)^{2} + {t}^{2} } \\ m= \sqrt{ {(24 \div 2)}^{2} + {9}^{2} } \\ m = \sqrt{144 + 81} = \sqrt{225} \\ m = 15 \\ \\ luas \: permukaan \: segitiga \\ (a \times t) + (a + m + m) \times tp) \\ (24 \times 9) + (24 + 15 + 15) \times 36) \\ 216 + (54 \times 36) \\ 216 + 1.944 \\ 2.160 \: {cm}^{2} [/tex]
Jawaban:
Diketahui
alas = 24 cm
tinggi alas = 9 cm
tinggi prisma = 36 cm
Ditanya
a) Volume = ?
b) Luas permukaan = ?
Jawab
V = Luas Alas x Tinggi Prisma
V = ( ½ x 24 x 9) x 36
V = 12 x 9 x 36
V = 3.888 cm³
Panjang IF
IF² = 12² + 9²
IF² = 144 + 81
IF = √225
IF = 15 cm
Luas permukaan prisma
= Luas selimut + 2 x luas alas
Luas selimut
= ( 24 x 36) + ( 15 x 36) + ( 15 x 36)
= 864 + 540 + 540
= 1944 cm²
Luas alas
= 2 x ( ½ x 24 x 9)
= 2 x ( 12 x 9)
= 2 x 108
= 216 cm²
Jadi luas permukaan prisma adalah 1944 + 216 = 2160 cm²