DE/AC = BD/AB
6/9 = 8/AB
2/3 = 8/AB
2AB = 8(3)
2AB = 24
AB = 24/2
AB = 12/1
AB = 12 CM
MAKA :
AD = AB - BD
= (12 - 8)CM
= 4 CM
Terdapat 2 segitiga sebangun, yaitu ΔABC dan ΔBDE.
[tex]\sf \frac{BD}{AB}=\frac{DE}{AC} \\\\\frac{BD}{AD+BD}=\frac{DE}{AC} \\\\\frac{8}{AD+8}=\frac{6}{9}\\\\\frac{8}{AD+8}=\frac{2}{3}\\\\\frac{4}{AD+8}=\frac{1}{3}\\\\AD+8= 4\cdot3\\\\AD=12-8\\\\AD=4\:cm[/tex]
Jadi, panjang AD adalah 4 cm [c.].
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DE/AC = BD/AB
6/9 = 8/AB
2/3 = 8/AB
2AB = 8(3)
2AB = 24
AB = 24/2
AB = 12/1
AB = 12 CM
MAKA :
AD = AB - BD
= (12 - 8)CM
= 4 CM
Verified answer
Kesebangunan Segitiga
Terdapat 2 segitiga sebangun, yaitu ΔABC dan ΔBDE.
[tex]\sf \frac{BD}{AB}=\frac{DE}{AC} \\\\\frac{BD}{AD+BD}=\frac{DE}{AC} \\\\\frac{8}{AD+8}=\frac{6}{9}\\\\\frac{8}{AD+8}=\frac{2}{3}\\\\\frac{4}{AD+8}=\frac{1}{3}\\\\AD+8= 4\cdot3\\\\AD=12-8\\\\AD=4\:cm[/tex]
Jadi, panjang AD adalah 4 cm [c.].