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√2' log(16²) = ² log 16^(4) = 4 x ² log 16 = 4 x 4 = 16
yg tengah menjadi :
√2' log 16 = √2' log (2^4) = ² log (2^8) = 8 x ² log 2 = 8
yg di depan menjadi :
√2' log 8 = √2' log 2³ = ² log 2^6 = 6 x ²log2 = 6
so,
6^6 = 46656
2) 1/(xy)' log (xyz) + 1/(yz)' log (xyz) + 1/(xz)' log (xyz)
= (xyz)' log (xy) + (xyz)' log (yz) + (xyz)' log (xz)
= (xyz)' log (xy * yz * xz)
= (xyz)' log (xyz)²
= 2 (xyz)' log (xyz)
= 2
notice : ' = as base