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dik= 1) kawat nida= 8 5/6 = 53/6
2) kawat gudang= 3 2/3 = 11/3
3) 6 benda membutuhkan masing-masing 1 3/4 = 6 x 7/4
= 42/4
dit=sisa kawat?
jwb= (kawat nida+kawat gudang)-kawat benda
= (53/6+11/3)-42/4
disamakan penyebutnya
= (106/12+44/12)-126/12
= 150/12-126/12
= 24/12
= 2 meter
nmr 6
a. sisa jeruk= 1) 8/8-5/8 = 3/8
2) 24/24-7/24= 17/24
berarti = 3/8+17/24
disamakan penyebut= 9/24+17/24
=26/24