Yg bsa saya akan kasih jawaban terbaik. ntar di kumpulin.... Question from @tiaanandalucky

October 2018 1 43 Report

Yg bsa saya akan kasih jawaban terbaik. ntar di kumpulin

is3nk 1.a) sudut POB = 90/2 = 45
OP = OB cos sudut POB
$OP = 20 cos 45$
$OP = 20 . \frac{1}{2} \sqrt{2}$
$OP = 10 \sqrt{2}$

1.b) luas tembereng = luas juring AOB - segitiga AOB
luas tembereng = $\frac{90}{360} \pi r^{2}- \frac{1}{2}at$
dimana, r = a = t = OB = 20
maka,
luas tembereng = $\frac{1}{4}. 3,14. 20^{2} - \frac{1}{2}.20.20$
luas tembereng = 314 - 200
luas tembereng = 114

2.a) tali busur QR = 60/360 keliling lingkaran
= $\frac{1}{6} \pi d$
= $\frac{1}{6} .3,14.20$
=10,467

2.b) PT = PR cos 60/2
= 10 cos 30
= $10. \frac{1}{2} \sqrt{3}$
= $5 \sqrt{3}$

2.c) luas tembereng = $\frac{60}{360}. \pi . PR^{2} - \frac{1}{2}.QR.PT$
luas tembereng = $\frac{1}{6}. 3,14. PR^{2} - \frac{1}{2}.(2.PR.cos60).PT$
luas tembereng = $\frac{1}{6}. 3,14.10^{2} - \frac{1}{2}.(2.10.\frac{1}{2}).5 \sqrt{3}$
luas tembereng = $\frac{1}{6}. 314 - \frac{1}{2}.10.5 \sqrt{3}$
luas tembereng = $\frac{314}{6} - 25 \sqrt{3}$

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Complete the conversations based on the situations and the pictures below. then practice one of them in front of the class. gesek aja gambarnya!

Answer

Complete each sentence woth a suitable adverb

Dizoom aja dan digeser, mohon yah yg baikk tlg bantuannya .....

Geserrr aja !!!!!.....

Gampangggggggggggggggggggg

Gampangggggggg....................

Gampanggggggg .. tlg dibantuuu

Gampang!geser aja gambarnya

Digeser aja! soalnya gampang

Gampang!di geser aja gambarnya.

Complete the conversations based on the situations and the pictures below. then practice one of them in front of the class. gesek aja gambarnya!

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