Question

Yg bisa jawab soal kimia no. 4

Answer 1

(NH4)2Cr2O7 => Cr2O3 + 4 H2O + N2
massa (NH4)2Cr2O7 = 15 gram
Mr (NH4)2Cr2O7 = 252
mol (NH4)2Cr2O7 = 15 gr / 252 gr/mol = 0,06 mol
perbandingan koefisien reaksi 1 : 1 : 4 : 1

mol H2O = 4/1 x mol (NH4)2Cr2O7 = 4/1 x 0,06 = 0,24 mol
mol N2 = 1/1 x mol (NH4)2Cr2O7 = 1/1 x 0,06 = 0,06 mol
R = 0,082
P = 1 atm
T = 180°C = 180 + 273 = 453 K

PV=nRT
V H2O = 0,24 x 0,082 x 453 / 1 = 8,915 liter
V N2 = 0,06 x 0,082 x 453 / 1 = 2,229 liter
total V gas yang di bebaskan = 11,144 liter