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BD² = 4² + 2²
BD² = 16 + 4
BD = √20
BD = √4 x √5
BD = 2√5
Sekarang kita tentukan nilai BE, lihat segitiga EDB
BE² = 5² + (2√5)²
BE² = 25 + (4x5)
BE² = 25 + 20
BE = √45
BE = √9 x √5
BE = 3√5
Jadi, panjang BD dan BE secara berturut-turut dengan nilai akar sederhana adalah 2√5 dan 3√5.
BD² = 2² + 4²
BD² = 4 + 16
BD² = 20
BD = √20
BD = √4 × √5
BD = 2√5
BE² = DE² + BD²
BE² = 25 + 20
BE = √45
BE = √9×√5
BE = 3√5