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Jawab4.
titik potong dengan sumbu x dan sumbu y
(i)
x + y = 12
x = 0, y = 12 , A(0,12)
y = 0 , x = 12, B(12,0)
(ii)
x + 2y = 16
x = 0, y = 8 , C (0,8)
y = 0, x = 16, D (16, 0)
(iii) titik potong keduanya
x + y = 12
x + 2y = 16 ||(-)
-y = - 4
y = 4
x + y = 12
x = 12- y = 12 - 4
x = 8
E(8, 4)
daerah himpunan
x + y ≤ 12
x + 2y ≥ 16
dengan batas titik
A(12,0), f(x,y) = 5(x) + 2(y) = 5(12) + 2(0)= 60
E (8,4), f(x,y) = 5(8) +2(4) = 48
C(16,0), f(x,y) = 5(16) +2(0) = 80
nilai mak = 80
5.
titik potong dengan sumbu x dan sumbu y
x + y = 50
x= 0, y = 50 , A = (0, 50)
y= 0, x = 50, B = (50, 0)
-x + 2y = 40
x= 0, y = 20 , C =(0, 20)
y = 0,x = -40, D= (-40, 0)
titik potong keduanya
x + y = 50
-x + 2y = 40 ||(+)
3y = 90
y = 30
x = 50-y
x= 20
E(20,30)
daerah HP dengan batas titik
C(0,20), f(x,y)= 3x + 5y = 3(0) + 5(20) = 100
B(50,0) , f(x,y) = 150
E(20,30), f(x,y)= 3(20) + 5(30) = 210
nilai maksimum = 210