hendrisyafa
3. y = - 5 cos x nilai min cos x = -1 saat x = π, --> y = 5 (π, 5) nilai max cos x = 1 --> saat x = 0, 2π --> y = -5 (0,-5) (2π,-5) nilai seimbang cos x = 0 saat x =1/2 π, 3/2 π --> y = 0 , (1/2π,0) (3/2 π, 0)
4. y = - 4 sin x nilai min sin x = -1 saat x = 3/2π, y = 4 (3/2 π, 4) nilai max sin x = 1 saat x = 1/2π, y = -4 (1/2π, -4) nilai seimbang sin x = 0 saat x = 0, π, 2π , y = 0 (0,0) (π,0) (2π,0)
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hendrisyafa
cos π = cos 180 = -1, sehingga saat cos x = -1, maka x = π
hendrisyafa
jadi y = -5 cos x = -5 cos π = -5 (-1) = 5
nilai min cos x = -1 saat x = π, --> y = 5 (π, 5)
nilai max cos x = 1 --> saat x = 0, 2π --> y = -5 (0,-5) (2π,-5)
nilai seimbang cos x = 0 saat x =1/2 π, 3/2 π --> y = 0 , (1/2π,0) (3/2 π, 0)
4. y = - 4 sin x
nilai min sin x = -1 saat x = 3/2π, y = 4 (3/2 π, 4)
nilai max sin x = 1 saat x = 1/2π, y = -4 (1/2π, -4)
nilai seimbang sin x = 0 saat x = 0, π, 2π , y = 0 (0,0) (π,0) (2π,0)