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AOB=2×ACB
AOB=2×55
AOB=110⁰
2) OP=OR=OQ sehingga ΔOPR dan ΔORQ sama kaki
maka ∠ORP=∠OPR=23⁰ sehingga ∠QOR=23+23=46⁰
∠OQR+∠ORQ=180-∠QOR
2×∠OQR=180-46
∠OQR=67⁰=∠PQR
4) sudut pusat = 2×sudut keliling
∠ATB=2×∠ACB
∠ATB=2×60
∠ATB=120⁰
5) sudut pusat = 2×sudut keliling
∠DGF=2×∠DEF
70=2×∠DEF
35⁰=∠DEF