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u = x² + 2x + 6
du = 2x + 2 dx
du = 2(x+1) dx
(x+1) dx = 1/2 du
btas intergral x² + 2x + 6
x = 0 --> u = 6
x = 1 --> u = 9
= ₆⁹∫ 1/2 (u⁻²) du
= -1/ (2u)]⁹₆
= -1/18 - (-1/12)
= (-2 + 3)/(36)
= 1/36