Question

Yang master matematika, ada yg bisa jawab 2 soal ini? itu materi integral tentu dengan penyelesaian substitusi sederhana

Answer 1

1)
₁∫² (3x -3)³ dx =
u = 3x - 3 --> du = 3 dx --> dx = 1/3 du
x = 2 --> u = 3
x =1 --> u = 0

₁∫² (3x - 3)³ dx = ₀³∫ 1/3 U³ du = 1/12 |U⁴|³₀ = 1/12 (81) = 81/12=6,75

2)₁²∫2x ( x²+ 3)⁴ = 
U = x²+ 3 --> du = 2x dx 
x =1 --> u = 4
x = 2 --> 7
₁²∫ 2x(x²+3)⁴ dx = ₄⁷∫ u⁴ du = 1/5 | u⁵|⁷₄= 1/5 ( 7⁵ - 4⁵)= 3.156,60