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f(x + 1) + 12 = f(x)
f(x + 1) = f(x) – 12
f(2) = 2000 – 12
f(3) = f(2) – 12 = (2000 – 12) – 12 = 2000 – 2 . 12
f(4) = f(3) – 12 = (2000 – 2 . 12) – 12 = 2000 – 3 . 12
f(5) = f(4) – 12 = (2000 – 3 . 12) – 12 = 2000 – 4 . 12
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f(n) = 2000 – (n – 1) . 12
(100) = 2000 – (100 – 1) . 12
= 2000 – 99 . 12
= 2000 – 1188
= 812. (B)