Question

(y-3)/(4y-y^2)-(y-4)/(y^2-16)

y=-3,3

Answer 1

(y-3)/[y(4-y)] - (y-4)/[(y-4)(y+4)]=-(y-3)/[y(4-y)]-1/(y+4)=

[(y-3)(y+4)-y(4-y)]/[y(4-y)(y+4)] = (y²+4y-3y-12-4y+y²)/[y(16-y²)] =

(2y²-3y-12)/[y(16-y²)]

[(-3,3)²-3*(-3,3)-12]/[-3,3(16-(-3,3)²)]= (10,89+9,9-12)/[-3,3(16-10,89)]=

8,79 : (-16,962) = - 1465/2827