Question

X³y - X²y + 5y -3
Encontrar valor numerico
a) x= 1, y = 1
b)x= 2; x = 3
c) x=2; y = 0​

Answer 1

Respuesta:

[tex]x^3y - x^2y + 5y - 3\\\\\\a) x = 1, y = 1\\\\x^3y - x^2 y + 5y - 3\\\\(1)^3(1) - (1)^2(1) + 5(1) - 3\\\\(1)(1) - (1)(1) + 5 - 3\\\\1 - 1 + 2\\\\2[/tex]

[tex]b) x=2 , y = 3\\\\x^3y - x^2y + 5y - 3\\\\(2)^3(3) - (2)^2(3) + 5(3) - 3\\\\(8)(3) - (4)(3) + 15 - 3\\\\24 - 12 + 12\\\\24[/tex]

[tex]c) x= 2 , y = 0\\\\x^3y - x^2y + 5y - 3\\\\(2)^3(0) - (2)^2(0) + 5(0) - 3\\\\8(0) - 4(0) + 0 - 3\\\\-3[/tex]

Explicación paso a paso: