" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
dla x =1 mamy 1 + 1+1 +1=4
dla x = -1 mamy -1 +1 -1 + 1 =0
odp. x =1
x²(x+1)+(x+1)=0
(x²+1)(x+1)=0
x²+1=0 lub x+1=0
sprzeczne, bo x²+1>0 dla kazdego x
x=-1
x(x²+x+1)+1=0
(x+1)(x²+x+1)=0
x+1=0∧x²+x+1=0
x=-1____∧Δ=b²-4ac
__________Δ=1²-4*1*1
__________Δ=1-4
__________Δ=-3
__________Δ<0 brak pierwiastków