Określ dziedzinę funkcji f i oblicz f(1), f(3), f(-3), f(-1/2), f(pierwiastek z 2):
a) f(x)=3/x
b) f(x)=x kwadrat - 2/x-2
c) f(x)=pierwaistek z 3-x
d) f(x)=/x/+x
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a)
f(1) = 3/1
f(1)= 3
f(3) = 3/3
f(3)= 1
f(-3)= 3/-3
f(-3)= -1
f( -1/2)= 3/-1/2
f(-1/2)= -6
f(pier 2)= 3/pier2 - konic.
b) f(1) =x kwadrat - 2/x-2
f(1) = 3
f(3)= x kwadrat - 2/x-2
f(3)= 11
f(-3)= x kwadrat - 2/x-2
f(-3) = 9 i 2/5
f(-1/2) =x kwadrat - 2/x-2
f(-1/2) = 1 i 1/20