x5 +4x3 -x2 -4 = 0 rozwiąż równanie
x⁵+4x³-x²-4=0
x³(x²+4)-(x²+4)=0
(x³-1)(x²+4)=0
x³-1=0 lub x²+4=0
x³=1 lub x²=-4
x=1 sprzeczne
x5 +4x3 -x2 -4 = 0
x^3(x^2 + 4) - (x^2 + 4) = 0
(x^2 + 4)(x^3 - 1) = 0
x^2 + 4 = 0 lub x^3 - 1 = 0
Δ = - 16 < 0 x^3 = 1
nie ma rozw. x = 1
odp. x = 1
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x⁵+4x³-x²-4=0
x³(x²+4)-(x²+4)=0
(x³-1)(x²+4)=0
x³-1=0 lub x²+4=0
x³=1 lub x²=-4
x=1 sprzeczne
x5 +4x3 -x2 -4 = 0
x^3(x^2 + 4) - (x^2 + 4) = 0
(x^2 + 4)(x^3 - 1) = 0
x^2 + 4 = 0 lub x^3 - 1 = 0
Δ = - 16 < 0 x^3 = 1
nie ma rozw. x = 1
odp. x = 1