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(x² + 3x + 1) / x = 1/a
x + 3 + (1/x) = 1/a
x + (1/x) = (1/a) - 3 ........pers i
x² / (x^4 + 3x² + 1) = 1 /(x² + 3 + 1/x²)
= 1/ {(x² + 1/x²) + 3}
= 1/ {(x + 1/x)² - 2 + 3}
= 1 / [(1/a) - 3}² + 1]
= 1/[(1/a)² - 6/a + 9 + 1]
= 1/ [(1/a)² - 6/a + 10]
= 1 / [(1 - 6a + 10a²)/a²]
= a² / ((1 - 6a + 10a²)