Rozwiąż równanie :
x/3x-2 = 3x-2/x+4
Z wykorzystaniem wzoru na deltę = b2 - 4ac
x(x+4)=(3x-2)^{2}
+4x=9 - 12x + 4
8-16x+4=0 /4
2-4x+1=0
delta=16-8=8
x1=(-b-pierw z delty)/2a= (4-2pierwz2)/4= 1-1/2 *pierwz2
x2=(-b+pierwzdelty)/2a= (4+2pierwz2)/4= 1+1/2* pierw z 2
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x(x+4)=(3x-2)^{2}
+4x=9 - 12x + 4
8-16x+4=0 /4
2-4x+1=0
delta=16-8=8
x1=(-b-pierw z delty)/2a= (4-2pierwz2)/4= 1-1/2 *pierwz2
x2=(-b+pierwzdelty)/2a= (4+2pierwz2)/4= 1+1/2* pierw z 2