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entonces: x + y = 5√3 / elevamos al ²
(x + y)² = 25*3
x² + 2xy + y² = 75
x² + y² = 75 - 2xy
x² + y² = 75 - 2*16
x² + y² = 43
2) ( x + y)² = 10 ^ x² + y² = 6
resolvemos el cuadrado: ( x + y )² = 10
x² + 2xy + y² = 10
2xy + x² + y² = 10
2xy + 6 = 10
2xy = 4
xy = 2
3) x + 1/x = 3 / elevamos al ²
( x + 1/x )² = 9
x² + 2 + 1/x² = 9
x² + 1/x² = 7 /elevamos al ²
( x² + 1/x²)² = 49
x^4 + 2 + 1/x^4 = 49
x^4 + 1/x^4 = 47
4) l. y ll. son falsas ya que :
( a - b )² = a² - 2ab + b²
( x + a) ( x + b ) = x² + xb+ xa + ab = x² + x( b + a ) + ab