Rozwiąż równanie: k) (x-3) / (x-7) = (4x) / (x+3) Potrzebuje na teraz
(x-3)/(x-7)=4x/(x+3)
(x-3)*(x+3)=4x*(x-7)
x^2-9=4x^2-28x
3x^2-28x+9=0
d=b^2-4ac
d=784-108
d=676
Vd=26
x1=[-b-Vd]/2a=[28-26]/6=1/3
x2=[-b+Vd]/2a=[28+26]/6=27
-------------
d - delta
^2 - do potęgi drudiej
V - pierwaiastek
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(x-3)/(x-7)=4x/(x+3)
(x-3)*(x+3)=4x*(x-7)
x^2-9=4x^2-28x
3x^2-28x+9=0
d=b^2-4ac
d=784-108
d=676
Vd=26
x1=[-b-Vd]/2a=[28-26]/6=1/3
x2=[-b+Vd]/2a=[28+26]/6=27
-------------
d - delta
^2 - do potęgi drudiej
V - pierwaiastek